Question

sin + cos = P , than sin^4 + cos ^ 4 =

Answer 1

Answer:

This is not a question ok

Answer 2

Answer:

1-1/2(p^2 - 1)^2

Step-by-step explanation:

sinθ+cosθ=a

sin  4  θ+cos  4  θ=(sin^ 2  θ+cos^ 2  θ) ^2  −2sin ^2  θcos ^2 θ

= 1 - 2sin^2  θcos^ 2 θ

Now, (sinθ+cosθ) ^2  =sin^ 2  θ+cos^ 2  θ+2sinθcosθ

p^ 2  = 1+2sinθcosθ

sinθcosθ= 1/2 (p^ 2 −1)

Hence, substituting the value of sinθcosθ, we get,

sin  4  θ+cos  4  θ=1 - 1/2 ​  (p^2  −1)  2