Math, asked by arham21, 11 months ago

(sin+cos)(sec+cosec)=2 cosec+sec​

Answers

Answered by mpreet196
5

Step-by-step explanation:

(sin+cos)(sec+cosec)

(sin+cos)(1/cos + 1/sin)

(sin+cos)(sin+cos/cos sin)

(sin+cos)^2/cos sin

sin^2 + cos^2 + 2 sincos/cos sin

1+2 sin cos / cos sin

1/cos sin + 2 sin cos/cos sin

sec cosec + 2

Hence proved !!

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