Math, asked by imazraza687, 11 months ago

(sin∅ + cos∅)(sec∅ + cosec) = 2 + sec∅ cosec∅​

Answers

Answered by saiPradhan182
4

Step-by-step explanation:

(sin o + cos o ) ( sec o+ cosec o)

=(sin o+ cos o) (1/ cos o + 1/ sin o)

= (sin o + cos o)(sin o+ cos o/sin o. cos o)

=(sin o+ cos o)^2/ sin o . cos o

=1+2sin o cos o/ sin o.cos o

=1/sin o. cos o+2 sin o cos o/ sin o cos o

=1/sin o . 1/cos o+2

=2+cosec o . sin o (proved)

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