sin+cos/sin-cos+sin-cos÷sin+cos=2sec^2÷tan^2-1
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Answered by
11
Hi, Here is your answer
Ans cos (1+sin)
(1+sin) + cos
= cos2 + (1+sin)2
cos*(1+sin)
= cos2 + 1 + 2sin + sin2
cos*(1+sin)
we know that cos2 + sin2 = 1
= (1+1+2sin)
cos*(1+sin)
= (2+2sin)
cos*(1+sin)
= 2(1+sin)
cos*(1+sin)
= 2
cos
= 2sec
OR
I assume the grouping is
cos/(1 + sin) + (1 + sin)/cos = 2 sec common denominator is cos(1 + sin)
[ cos · cos + (1 + sin)(1 + sin) ] / [cos(1 + sin)] = 2 sec
[ cos2 + sin2 + 2 sin + 1 ] / [cos(1 + sin)] = 2 sec
[ 1 + 2 sin + 1] / [cos(1 + sin)] = 2 sec
[ 2 sin + 2] / [cos(1 + sin)] = 2 sec
[ 2(sin + 1] / [cos(1 + sin)] = 2 sec
2 1/cos = 2 sec
2 sec = 2sec
Ans cos (1+sin)
(1+sin) + cos
= cos2 + (1+sin)2
cos*(1+sin)
= cos2 + 1 + 2sin + sin2
cos*(1+sin)
we know that cos2 + sin2 = 1
= (1+1+2sin)
cos*(1+sin)
= (2+2sin)
cos*(1+sin)
= 2(1+sin)
cos*(1+sin)
= 2
cos
= 2sec
OR
I assume the grouping is
cos/(1 + sin) + (1 + sin)/cos = 2 sec common denominator is cos(1 + sin)
[ cos · cos + (1 + sin)(1 + sin) ] / [cos(1 + sin)] = 2 sec
[ cos2 + sin2 + 2 sin + 1 ] / [cos(1 + sin)] = 2 sec
[ 1 + 2 sin + 1] / [cos(1 + sin)] = 2 sec
[ 2 sin + 2] / [cos(1 + sin)] = 2 sec
[ 2(sin + 1] / [cos(1 + sin)] = 2 sec
2 1/cos = 2 sec
2 sec = 2sec
Answered by
7
I do not know what to do please help
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