Question

sinθ·cosθ(tan θ + cot θ) = ??

Answer 1

Answer:

The answer is 1.

Step-by-step explanation:

⇒ sinθ.cosθ(tanθ + cotθ)

  = sinθ.cosθ.tanθ + sinθ.cosθ.cotθ

  = sinθ.cosθ.sinθ/cosθ + sinθ.cosθ.cosθ/sinθ

  = sin²θ + cos²θ

  = 1

I do so hope that this helps you, mate!

Answer 2

sin∅.cos∅(tan∅+cot∅)

sin∅.cos∅ ( sin∅/cos∅ + cos∅/sin∅)

sin ∅. cos∅( sin²∅+ cos∅+ cos²∅+ sin ∅/cos∅. sin ∅). .: ( sin∅. cos∅ cancelled by sin∅. cos∅)

sin²∅+ cos ∅+ cos²∅+ sin∅

1+ cos∅+ sin∅

=cos∅+ sin ∅