sinθ·cosθ(tan θ + cot θ) Please help guys.......
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Answered by
9
ANSWER:
tan* + cot* is a correct answer.
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Answered by
1
Answer:
sinθ*cosθ(tanθ+cotθ)
= sinθ*cosθ(sinθ/cosθ+cosθ/sinθ)
=sinθ*cosθ(sin^2θ+cos^2θ/sinθ*cosθ) (LCM)
=sin^2θ+ cos^2θ (as sin*cos gets cancelled)
= 1 (sin^2θ+cos^2θ=1)
Answer is 1
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