sin[cot-1{tan(cos-1)}]=x
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• consider the LHS
sin(cot^-1{tan[cos^-1x]})
= sin ( cot ^ -1{cot[90-cos^-1x]})
= sin( 90-cos^-1x)
= Cos( cos^-1x)
= X
= RHS
• note that: tanx = cot (90-x)
cosx= sin (90-x)
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