Question

sinθ∕cotθ+cosecθ= 2+ sinθ/cotθ-cosecθ

Answer 1

Here is the required answer

Answer 2

Hello friends!!

We have used the following trigonometric ratios:

$\\ (i) \: \cot \: A = \frac{ \cos \: A }{ \sin \: A \: }$


$\\ (ii) \cosec \: A= \frac{1}{ \sin \: A }$


$(iii) \: { \sin}^{2} A = 1 - { \cos }^{2} A \:$


We have use the following identities :


$(i) \: {a}^{2} - {b}^{2} = (a + b)(a - b)$


Now, see the attached file...

Hope it helps you

^_^