Math, asked by prashantasethi2227, 11 months ago

Sin coube a+coscoube a/sin a+cosa=1-sina×cosa

Answers

Answered by sandy1816

1

Step-by-step explanation:

sin³A+cos³A/sinA+cosA

=(sinA+cosA)(sin²A-sinAcosA+cos²A)/(sinA+cosA)

=(sinA+cosA)(1-sinAcosA)/(sinA+cosA)

=1-sinAcosA

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