sin cube theta + cos cube theta by sin theta + cos theta equal to 1 minus sec theta into cos theta
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sin^3 © + cos^3 © / sin © + cos ©
= (sin © + cos ©) ( sin^2 © + cos^2 © - sin © cos ©)/sin © + cos ©
= 1- sin© cos ©
= (sin © + cos ©) ( sin^2 © + cos^2 © - sin © cos ©)/sin © + cos ©
= 1- sin© cos ©
Mrsubhransu:
it is sec theta not sin theta
well then there might be a printing mistake in the question
bcz 1-sin theta*cos theta is all that we can get of it
OKk thanks brother
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Answer:
Sin^3 © + cos^3 © / sin © + cos ©
= (sin © + cos ©) ( sin^2 © + cos^2 © - sin © cos ©)/sin © + cos ©
= 1- sin© cos ©
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