Question

sin cube theta + cos cube theta divided by sin theta + cos theta is equal to 1 minus sin theta into cos theta​

Answer 1

Step-by-step explanation:

sin3x + cos3x/sinx+cosx

= (sinx + cosx)( sin2x - sinxcosx+ cos2x)/ sinx + cosx

= 1-sinxcosx= RHS

Answer 2

Step-by-step explanation:

$\huge{\textbf{\textsf{{\orange{a}}{\blue{n}}{\pink{s}}{\purple{w}}{\red{e}}{\green{r}}:}}}$