Math, asked by mvvsr68, 5 hours ago

sin cube theta plus cos cube theta by sin theta + cos theta=

Answers

Answered by BARATHSHIVAM

1

Step-by-step explanation:

sin³A + cos³A = (sinA+cosA)(sin²A+cos²-sinAcosA)

sin³A+cos³A / sinA+ cosA

= (sinA+cosA)(sin²A+cos²-sinAcosA) / sinA + cosA

= sin²A +cos²A -sinAcosA

= 1- sinAcosA

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