Question

sin cube theta + sin3 theta / cos cube theta - cos3 theta
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Answer 1

Step-by-step explanation:

GIVEN :

• sin cube theta + sin3 theta / cos cube theta - cos3 theta

to find :

• cos cube theta - cos3 theta

solution :

• We have x = a `cos^3 theta

• => x/a = cos^3 theta

• Again, y = b sin^3 theta`

• => y/b = sin^3 theta

• Now, LHS = (x/a)^(2/3) + (y/b)^(2/3)`

• = (cos^3 theta )^(2/3) + (sin^3 theta )^

• (2/3) [from (i) and (ii)]

• = cos^2 theta + sin^2 theta

• =1

• Hence, LHS = RHS