Question

sin e +
cos e
= cos 0 + sin e
1 - tan o
cos - sin e​

Answer 1

Answer:

since + cost +since1 - tancost -since

Explanation:

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Answer 2

$\frac{cos}{1 - tan} - \frac{ {sin}^{2} }{cos - sin} \\ = \frac{ {cos}^{2} }{cos - sin} - \frac{ {sn}^{2} }{cos - sin} \\ = \frac{ {cos}^{2} - {sin}^{2} }{cos - sin} \\ = \frac{(cos + sin)(cos - sin)}{(cos - sin)} \\ = cos + sin$