Sin inverse 1 by 2 + Cos inverse 1 by 2 is equal to
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7
method 1:-
sin^-1(1/2) + cos^-1(1/2)
we know,
cos^-1(x) + sin^-1(x) = π/2
here x = 1/2
hence,
sin^-1(1/2) + cos^-1(1/2) = π/2
method 2 :-
Let sin^-1(1/2) = A
sinA = 1/2
sinA = sin(π/6)
A = π/6
again,
cos^-1(1/2) = B
cosB = 1/2
cosB = cos(π/3)
B = π/3
hence,
sin^-1(1/2) + cos^-1(1/2) = A + B = π/2
sin^-1(1/2) + cos^-1(1/2)
we know,
cos^-1(x) + sin^-1(x) = π/2
here x = 1/2
hence,
sin^-1(1/2) + cos^-1(1/2) = π/2
method 2 :-
Let sin^-1(1/2) = A
sinA = 1/2
sinA = sin(π/6)
A = π/6
again,
cos^-1(1/2) = B
cosB = 1/2
cosB = cos(π/3)
B = π/3
hence,
sin^-1(1/2) + cos^-1(1/2) = A + B = π/2
Answered by
0
Answer:
5Π /12
cos ^-1 1/2 =x
sin^-1 1/2=x
then,
cos x=1/2
sin x/2=1/2
sinx/2=Π/12
cos x =Π/3
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