sin inverse(1+tan square x/1-tan square x
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- ton
[cos' [ 1 = tex]
-
+ ton²
Let I=
cos
2
1- ton x
1+ ton²x
dx
2
Cos²x
1 + sin ²x
I
los
1
dx
S
los
cos²x
Cos ²x + sin²x.
2
-
dx
cos²x - sin ² x = cos 2x
cos²x + sin ² x
1
(2
I =
S
cos" [cas 2x] dx
2x]dx
I = (2x d
dx
Sx³ dx
n
2+1
3
=
C is a constant
1+1
I = 2x²
+ C
=
2x
2
2
+ C = x² + C
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