Question

sin inverse 2x+sin inverse 3x =pi by 3
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Answer 1

Answer:

sin^-1(x)+sin^-1(2x)=π/3

sin^-1(2x)=π/3-sin^-1(x)

2x=sin(π/3-sin^-1(x))

2x=sin(π/3)cos(sin^−1(x))−cos(π/3)sin(sin^−1(x))

2x=√3/2cos(cos^−1(whole root over 1−x^2))−1/2(x)

2x+x/2=√3/2(whole root over 1-x²)

5x=√3(whole root over 1-x²)

25x²=3-3x²

28x²=3

x=√(3/28)