Question

sin inverse √3/2 = ?
where -π/2≤x≤π/2​

Answer 1

Answer:

$x= \frac{2\pi }{3}$

Step-by-step explanation:

$sin^{-1}(\frac{\sqrt{3} }{2} )= x\\sin x= (\frac{\sqrt{3} }{2} )\\x= \frac{2\pi }{3}$