Sin inverse 3/5+tan inverse 3/4
Answers
Answer:
These is your answer pl. mark as brainliest
Explanation:
2sin
−1
5
3
−tan
−1
31
17
=
4
∏
as we know triangle triplet is (3,4,5). so we use this in our proving at the time use.
now we have to prove L.H.S =R.H.S
\begin{lgathered}2\sin^{-1}\frac{3}{5}-\tan^{-1}\frac{17}{31}=\frac{\prod }{4}\\\\2\tan^{-1}\frac{3}{4}-\tan^{-1}\frac{17}{31}=\frac{\prod }{4}\\\\\tan^{-1}\frac{2*\frac{3}{4}}{1-(\frac{3}{4})^{2}}-\tan^{-1}\frac{17}{31}=\frac{\prod }{4}\\\\\tan^{-1}\frac{24}{7}-\tan^{-1}\frac{17}{31}=\frac{\prod }{4}\\\\\tan^{-1}\frac{\frac{24}{7}-\frac{17}{31}}{1+\frac{24}{7}*\frac{17}{31}}=\frac{\prod }{4}\\\\\tan^{-1}(1)=\frac{\prod }{4}\\\\\frac{\prod }{4}=\frac{\prod }{4}\end{lgathered}
2sin
−1
5
3
−tan
−1
31
17
=
4
∏
2tan
−1
4
3
−tan
−1
31
17
=
4
∏
tan
−1
1−(
4
3
)
2
2∗
4
3
−tan
−1
31
17
=
4
∏
tan
−1
7
24
−tan
−1
31
17
=
4
∏
tan
−1
1+
7
24
∗
31
17
7
24
−
31
17
=
4
∏
tan
−1
(1)=
4
∏
4
∏
=
4
∏