Question

sin inverse 4/5+ cos inverse 3/5​

Answer 1

Answer:

Consider a right angled triangle ABC where the B is the right angle and the sides being a=3, b=5(hypotenuse) and c=4.

Sin(C) =oppside/hypotenuse = c/b =4/5

Cos(C) = adj. side/hypotenuse = a/b=3/5

So C= Sin Inv(4/5) = Cos Inv(3/5)