Math, asked by ankit5184, 1 year ago

sin inverse dx/dy = (x+y)

Answers

Answered by saurabhsemalti
0
dx/dy=sin(x+y)
let x+y=t
(dx/dy)+1=dt/dx
question becomes

(dt/dx)-1=sint
dt/(1+sint)=dx
integrate This Term by writing sin x in terms of half angle secx and Tanx
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