sin inverse of cos 53π divided by 5 please answer me
Answers
Answered by
0
Answer:
sin
−
1
(
cos
(
53
π
5
)
)
=
−
π
10
Explanation:
We know that,
(
1
)
cos
(
2
k
π
+
θ
)
=
cos
θ
(
2
)
cos
(
π
2
+
θ
)
=
−
sin
θ
(
3
)
sin
−
1
(
−
x
)
=
−
sin
−
1
x
(
4
)
sin
−
1
(
sin
(
x
)
)
=
x
,
w
h
e
r
e
,
x
∈
[
−
π
2
,
π
2
]
Here,
53
π
5
=
10
π
+
3
π
5
...
...
1
s
t
.quadrant
∴
sin
−
1
(
cos
(
53
π
5
)
)
=
sin
−
1
(
cos
(
10
π
+
3
π
5
)
)
=
sin
−
1
(
cos
(
3
π
5
)
)
...
.
.
→
A
p
p
l
y
(
1
)
=
sin
−
1
(
cos
(
6
π
10
)
)
=
sin
−
1
(
cos
(
π
2
+
π
10
)
)
=
sin
−
1
(
−
sin
(
π
10
)
)
...
...
.
.
→
A
p
p
l
y
(
2
)
=
−
sin
−
1
(
sin
(
π
10
)
)
...
...
.
→
A
p
p
l
y
(
3
)
=
−
π
10
...
...
...
.
→
A
p
p
l
y
(
4
)
⇒
sin
−
1
(
cos
(
53
π
5
)
)
=
−
π
10
∈
[
−
π
2
,
π
2
]
Similar questions