sin inverse ( sin x + cos )/root 2
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Answer:
okkkk
Step-by-step explanation:
sin ^-1 (sin x+cos x)/root 2
sin ^-1 (sinx/root 2+ cos x /root 2 )
sin^-1 (sinx cos 45 +sin 45 cos)
sin ^1 (sin (x+45))
x+45
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