Question

sin(logi^i)=-1 solve this question plij
​

Answer 1

Answer:

see in xplanation

Step-by-step explanation:

Let a+ib=sin(logi  

i

)=sin(ilogi)

=sin(i(log∣i∣+iamp(i)))…(i=∣i∣amp(i))

=sin(i(0+  

2

iπ

​  

))

=sin(0+  

2

i  

2

π

​  

)

=sin(0−  

2

π

​  

)

a+ib=−1

⇒a=−1,b=0

∴sin(logi  

i

)=−1+0=−1

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