Math, asked by TEJASRI23, 10 months ago

[sin(n+1)a -sin(n-1)a] /
[cos(n+1a + 2 cos na + cos(n-1)a ]
a) Tan(a/2)
b) cot(a/2)
c) cota
d) tan a

Answers

Answered by ritesh2489kumar

1

Answer:

answer of sin(n+1)a -sin(n-1)a] /

[cos(n+1a + 2 cos na + cos(n-1)a ]

a) Tan(a/2)

b) cot(a/2)

c) cota

d) tan a

Step-by-step explanation:

d

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