(sin o + cos o + 1) (sin o+cos-1). Seco cosec o=2
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consider LHS
= (sin o + cos o + 1) (sin o+cos-1). Sec o cosec o
= { ( sin o + cos o ) + 1 } {( sin o + cos o ) - 1 } sec o × cosec o
= { ( sin o + cos o ) ^2 - 1 ^2 } sec o × cosec o
= ( sin^2 o + cos^2 o - 2 sino × coso ) sec o × cosec o
= ( 1 + 2 sino × coso - 1 ) sec o × cosec o
= 2 sin o × cosec o × sec o × cosec o
= 2 × ( sin o × cosec o ) × ( cos o × sec o )
= 2 × 1 × 1 ( sin o × cosec o = 1 and sec o × cosec o = 1 )
= 2
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