Question

sin o sec(90-o) tan o by cosec (90-o)cos o cot (90-o) - tan(90-o) by cot o

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Answer 1

sin o sec(90-o) tan o by cosec (90-o)cos o cot (90-o) - tan(90-o) by cot o

sin o cosec o tan o/sec o cos o tan o

=sin o x 1/sin o tan o /sec o x 1/sec 0 tan o

=tan o/tan o

=1 .......... 1

next one,

-tan(90-0) / cot 0

-cot0/cot o

=-1 ........ 2

from I and 2

1-1=0