Question

sin θ= p/q find cos θ + sin θ in terms of p and q

Answer 1

Answer:

sin x+ cos x= {p+√(q²-p²)}/q

Step-by-step explanation:

sin x= p/q

therefore, in a right angle triangle;

perpendicular= p and hypotenuse=q

so, base= √(q²- p²)

thus, cos x= √(q²-p²)/q

therefore, sin x+ cos x= {p+√(q²-p²)}/q