Math, asked by lazibansari02, 4 months ago

Sinθ/ (secθ+tanθ-1) + cosθ/ (cosecθ+cotθ-1) = 1
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Answered by Anonymous

2

Answer in attachment...!!

Formula applied in solution are:-

sin²θ + cos²θ=1
secθ = 1/cosθ
tanθ = sinθ/cosθ
cosecθ = 1/sinθ
cotθ = cosθ/sinθ
(a+b)(a-b)=a²-b²

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