Question

sin
(Seco+ tano)= 1+sino
1-sino​

Answer 1

Answer:

Here is your answer

Step-by-step explanation:

(sec theta -tan theta) ^2=1+sin theta/1-sin theta

(1/cos theta-cos theta/sin theta)^2=(1-sin)(1-sin) /cos^2 theta

(1-sin theta) (1-sin theta) /(1-sin theta) (1+sin theta)

1-sin theta/1+sin theta=1+sin theta/1+sin theta

LHS=RHS