Sin * sin ÷ cos + cos = sec
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Answer:sin A cos A , LHS = RHS
Step-by-step explanation:
LHS = (Cosec A - Sin A) (Sec A - Cos A)
= (1/sin A - Sin A)(1/cos A - cos A)
= [(1 - sin2 A)/sin A] [(1 - cos2 A)/cos A]
= [(cos2 A)/sin A][sin2 A/cos A]
= sin A cos A
RHS = 1 / (Tan A + Cot A)
= 1 / (sin A/cos A + cos A/sin A)
= 1 / [(sin2 A + cos2 A)/sin A cos A]
= 1 / [1/sin A cos A]
= sin A cos A
LHS = RHS
Hence proved.
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