sin square 120+cos square300+tan square135=? Please answer it.Fast.
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Answer:
Given: sin^2(120°)+co^2(300°)+tan^2(135°)
Step-by-step explanation:
So,
sin²(120°)+cos²(300°)+tan²(135°)
= sin²(180°-60°)+cos²(360°-60°)+tan²(180°-45°)
= sin²60°+cos²60°+tan²45°
= (√3/2)^2+(1/2)^2+(1)^2
= (3/4)+(1/4)+1
= [(3+1)/4]+1
= (4/4)+1
= 1+1
= 2 .....................(Ans.)
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