sin square 20 + sin square 70 upon sin theta into cos 90 minus theta + cos theta into sin 90 minus theta
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sin^2 20+sin^2 70/sin theta×cos(90-theta)+cos theta×sin(90-theta)
=sin^2 20+cos^2 20/sin theta×sin theta+cos theta×cos theta
=1/sin^2 theta+cos^2 theta
=1/1=1
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(Sin²20° + Sin²70°)/(SinθCos(90°-θ) + CosθSin(90°-θ)) = 1
Step-by-step explanation:
(Sin²20° + Sin²70°)/(SinθCos(90°-θ) + CosθSin(90°-θ))
Using Sinθ = Cos(90°-θ)
& Cosθ = Sin(90° - θ)
Sin20° = Cos(90° - 20°) = Cos70°
= (Cos²70° + Sin²70°)/(SinθSinθ + CosθCosθ)
=(Cos²70° + Sin²70°)/(Sin²θ + Cos²θ)
using Sin²θ + Cos²θ = 1
= 1 / 1
= 1
(Sin²20° + Sin²70°)/(SinθCos(90°-θ) + CosθSin(90°-θ)) = 1
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