Question

sin square 20 + sin square 70 upon sin theta into cos 90 minus theta + cos theta into sin 90 minus theta​

Answer 1

sin^2 20+sin^2 70/sin theta×cos(90-theta)+cos theta×sin(90-theta)

=sin^2 20+cos^2 20/sin theta×sin theta+cos theta×cos theta

=1/sin^2 theta+cos^2 theta

=1/1=1

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Answer 2

(Sin²20°  + Sin²70°)/(SinθCos(90°-θ)  + CosθSin(90°-θ)) = 1

Step-by-step explanation:

(Sin²20°  + Sin²70°)/(SinθCos(90°-θ)  + CosθSin(90°-θ))

Using Sinθ = Cos(90°-θ)

& Cosθ = Sin(90° - θ)

Sin20° = Cos(90° - 20°) = Cos70°

= (Cos²70°  + Sin²70°)/(SinθSinθ   + CosθCosθ)

=(Cos²70°  + Sin²70°)/(Sin²θ   + Cos²θ)

using Sin²θ   + Cos²θ = 1

= 1 / 1

= 1

(Sin²20°  + Sin²70°)/(SinθCos(90°-θ)  + CosθSin(90°-θ)) = 1

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