Question

sin square 30 degree - 2 cos cube 60 degree +3 tan power 4 45 degree

Answer 1

hope this answer will help you.

Answer 2

$\sin^230^\circ-2\cos^360^\circ+3\tan^4 45^\circ=3$

Step-by-step explanation:

Given : Expression $\sin^230^\circ-2\cos^360^\circ+3\tan^4 45^\circ$

To find : The value of the expression ?

Solution :

Using trigonometric values,

$\sin 30^\circ=\frac{1}{2}$

$\cos 60^\circ=\frac{1}{2}$

$\tan 45^\circ=1$

Substitute the value in the expression,

$\sin^230^\circ-2\cos^360^\circ+3\tan^4 45^\circ=(\sin 30^\circ)^2-2(\cos 60^\circ)^3+3(\tan 45^\circ)^4$

$\sin^230^\circ-2\cos^360^\circ+3\tan^4 45^\circ=(\frac{1}{2})^2-2(\frac{1}{2})^3+3(1)^4$

$\sin^230^\circ-2\cos^360^\circ+3\tan^4 45^\circ=\frac{1}{4}-2(\frac{1}{8})+3(1)$

$\sin^230^\circ-2\cos^360^\circ+3\tan^4 45^\circ=\frac{1}{4}-\frac{1}{4}+3$

$\sin^230^\circ-2\cos^360^\circ+3\tan^4 45^\circ=3$

#Learn more

If sin square 60 degree - sin square 30 degree​

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