Question

sin square (45degree/2)=?

Answer 1

Proceed like this...
[tex]sin ^{2} (\frac{45}{2}) \\ \\ (sin \frac{45}{2} )^2 \\ \\ [/tex]
Using the formula we get .. $sin \frac{A}{2} = \sqrt{ \frac{1-cosA}{2} }$

$\sqrt{ \frac{1-cos45}{2} } ^2$
$\frac{1- \frac{1}{\sqrt{2}} }{2}$
$\frac{ \frac{ \sqrt{2} -1}{ \sqrt{2} } }{2}$
$\frac{ \frac{2- \sqrt{2} }{2} }{2}$
$\frac{2- \sqrt{2} }{4}$