Question

sin square 60 degree + cos square 60 degree upon tan 60 degree

Answer 1

$\bf \large \it{Hey \: User!!!}$

we know that sin60° = √3/2, cos60° = 1/2 and tan60° = √3

$\bf \: therefore \: \frac{ { \sin(60) }^{2} + { \cos(60) }^{2} }{ \tan(60) } \\ \\ \bf \: = \frac{ { (\frac{ \sqrt{3} }{2}) ^{2} } + { (\frac{1}{2} )}^{2} }{ \sqrt{3} } \\ \\ \bf \: = \frac{ \frac{3}{4} + \frac{1}{4} }{ \sqrt{3} } \\ \\ \bf = \frac{ \frac{4}{4} }{ \sqrt{3} } \\ \\ \bf \: = \boxed{ \frac{1}{ \sqrt{3} } }$

$\bf \large \it{Cheers!!!}$

Answer 2

Answer:1÷√3

Step-by-step explanation: