Question

sin square 60 degrees + cos square 30 degrees minus cos square 30 degrees minus sin square 90 degrees ​

Answer 1

Step-by-step explanation:

${ \sin}^{2} (60) + { \cos}^{2} (30) - { \cos }^{2} (30) - { \sin }^{2} 90 \\ = {( \frac{ \sqrt{3} }{2}) }^{2} + ( { \frac{ \sqrt{3} }{2} )}^{2} - {( \frac{ \sqrt{3} }{2}) }^{2} - {(1)}^{2} \\ = \frac{3}{4} + \frac{3}{4} - \frac{3}{4} - 1 \\ = \frac{3}{4} - 1$

$= \frac{ - 1}{4}$

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