Question

Sin square 60°-cos square 60°= sin 30°

Answer 1

Answer:

To prove ☉☉→

${ \sin(60) }^{2} - { \cos(60) }^{2} = \sin(30)$

${ \sin(60) }^{2} = { \frac{ \sqrt{3} }{2} }^{2}$

${ \cos(60) }^{2} = { \frac{1}{2} }^{2}$

$\sin(30) = \frac{1}{2}$

LHS=

${ \frac{ \sqrt{3} }{2} }^{2} - { \frac{1}{2} }^{2}$

$\frac{3}{4} - \frac{1}{4}$

$\frac{3 - 1}{4} = \frac{2}{4}$

$\frac{2}{4} = \frac{1}{2}$

So , LHS = RHS

Hence proved

Answer 2

Answer:

nope....... sin 30 °= 1/√2

but according to me it is 1/4

sin square 60°=3/4

and cos square 60°= 1/2

and at last in subtracting u get.... 1/4

I hope u get this.....

old mark me the brainliest