Question

Sin square 63 + sin square 27 /cos square 17+cos square 73

Answer 1

sin^2 63° = [cos (90-63)]^2 = cos^2 27°

cos^2 17° = [sin(90-17)]^2 = sin^2 73°

putting the values,

We get,

(cos^2 27° + sin^2 27°)/( sin^2 73° + cos^2 73°)

but,

sin^2@ + cos^2@ = 1

therefore,

= 1/1

= 1

Answer 2

ANSWER

$\frac{ {sin}^{2} 63 ° + {sin}^{2} 27°}{ {cos}^{2}17° + {cos}^{2}73 ° }$

$\boxed{\red{{sin}^{2}(90 \degree \: - \theta)={cos}^{2} \theta }}$

$\boxed{ \red{ {cos }^{2}(90 \degree \: - \theta) ={sin}^{2} \theta }}$

$\frac{ sin² (90° - 63°)+ cos² 27°}{</p><p>cos(90° - 73°) + {cos }^{2} 73°}$

$\boxed{\red{{sin }^{2} \theta +{cos }^{2} \theta = 1 }}$

$\frac{ cos² \: 27° + sin² \: 27°}{</p><p>{sin }^{2} 73°+ {cos} ^{2} 73°}$

$\orange{\frac{1}{1} =1}$