Question

sin square 63° + sin square 27
----------------------------------------------
sec square 20° - cot square 70°


+2sin 36°× sin 42°× sec 48° × sec 54°​

Answer 1

Answer:

(sin²63°+sin²27°/sec²20°-cot²70°)+2sin36°sin42°sec48°sec54°

=[sin²63+sin²{(90°×1)-63°}/sec²20°-cot²{(90°×1)-20°}]+2sin36°sin42°

sec{(90°×1)-42°}sec{(90°×1)-36°}

=[sin²63°+cos²63°/sec²20°-tan²20°]+2sin36°sin42°cosec42°cosec36°

=1/(sec²20°-tan²20°)+2sin36°sin42°(1/sin42°)(1/sin36°)

=1+2×1×1

=1+2

=3 Ans.

[It should be sec²20°-cot²70° in the denominator]

Step-by-step explanation: