sin square A + cos square A = ( sinA+cosA) (1-sinA×cosA)
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Answer:
Step-by-step explanation:
A = 2πn+π/2, n∈Z
A = 2πn, n∈Z
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Answer:
sin^2 A +cos^2 A = (sinA+cosA)(1-sinA×cosA)
sin^2 A + cos^2 A = 1
• (sinA+cosA)(1-sinA×cosA)=1
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