Question

sin square A cos square B - cos square A sin square B =

Answer 1

Hello friend

Good morning

Your answer is given below you can check :

$= > { \sin(a) }^{2} \: { \cos(b) }^{2} - { \cos(a) }^{2} { \sin(b) }^{2} \\ \\ = > it \: is \: the \: identity \\ \\ so \: = > {\cos}^{2}\:(a + b)$

I hope it will help you

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Answer 2

Answer: sin²A-sin²B

Step-by-step explanation:

given that

sin²A cos²B - cos²A sin²B

=sin²A(1-sin²B)- [(1-sin²A)sin²B]

=sin²A-sin²A sin²B-[sin²B- sin²A sin²B]

=sin²A-sin²A sin²B-sin²B+ sin²A sin²B

=sin²A-sin²B