Math, asked by suyogvyas, 11 months ago

sin square A cos square b + cos square a sin square b + cos square A cos square b + sin square a sin square B

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Answers

Answered by vinayakvijayankumar
19

Answer:

Step-by-step explanation

sin^{2}A*cos^{2}B + cos^{2}A*sin^{2}B + cos^{2}A*cos^{2}B + sin^{2}A*sin^{2}B = 1

L.H.S

sin^{2}A*cos^{2}B+ cos^{2}A*cos^{2}B + cos^{2}A*sin^{2}B+sin^{2}A*sin^{2}B

cos^{2}B(sin^{2}A+ cos^{2}A) +sin^{2}B(cos^{2}A+sin^{2}A)

(cos^{2}B + sin^{2}B)(sin^{2}A+ cos^{2}A)

= 1

L.H.S=R.H.S

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