Math, asked by athang07, 1 year ago

sin square A + sin square A X tan square tan square A =tan square A​

Answers

Answered by Anonymous
1

hope this helps you.. :)

Attachments:
Answered by Shahoodalam
0

 \sin {}^{2} (a)  +  \sin {}^{2} (a)  \times  \tan {}^{2} (a)  =  \tan {}^{2} (a)  \\  \sin {}^{2} (a) (1 +  \tan {}^{2} (a))  =  \tan {}^{2} (a)  \\  \sin {}^{2} (a)  \csc {}^{2} (a)  = \tan {}^{2} (a)  \\  \sin {}^{2} (a)  \times  \frac{1}{ \sin {}^{2} (a) }  =  \tan {}^{2} (a)  \\ 1 =  \tan {}^{2} (a)  \\  \tan(a)  =  \sqrt{1}  \\  \tan(a)  = 1 \\

I hope that helps you...

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