sin square theta + cos square theta=1
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yes, sin ^2theta+cos^2theta=1
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Sin theta = perpendicular/hypotenuse
therefore, sin ^2 theta = perpendicular ^2/ hypotenuse ^2.
similarly,
cos theta = base / hypotenuse
cos ^2 theta = base^2 / hypotenuse ^2
given, sin ^2 theta + cos ^2 theta
= perp.^2/ hypotenuse ^2 + base^2 / hypotenuse ^2
= (perp.^2 + base^2) / hypotenuse ^2 ................... (i)
= now we know that in a right angled triangle, by pythagoras theorem, hypotenuse ^2 = perp.^2 + base^2
so, putting this in (i),
we get , hypotenuse ^2 / hypotenuse ^2
= 1
therefore hence proved
as LHS= RHS.
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