Question

sin square theta + cos square theta divided by sin square theta​

Answer 1

$\frac{ { \sin }^{2} \alpha + { \cos}^{2} \alpha }{ { \sin }^{2} \alpha } \\ \\ = > \frac{1}{ { \sin}^{2} \alpha } = { { \csc }^{2} \alpha }$

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Answer 2

(Sin²ø + Cos²ø)/Sin²ø

We can write sin²ø + cos²ø = 1

=> 1/Sin²ø

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