sin square x +cos square square
Answers
Answered by
0
dear
you know,
sinx=p/h
cosx=b/h
also relation between p,b, and h
p^2+b^2=h^2
sin^2x=p^2/h^2
cos^2x=b^2/h^2
sin^2x+cos^2x=(p^2+b^2)/h^2=1
you know,
sinx=p/h
cosx=b/h
also relation between p,b, and h
p^2+b^2=h^2
sin^2x=p^2/h^2
cos^2x=b^2/h^2
sin^2x+cos^2x=(p^2+b^2)/h^2=1
Answered by
0
sin^2(x) + cos^2(x)
= (P/h)^2 + (b/h)^2
= (p^2/h^2) + (b^2/h^2)
= (p^2 + b^2)/h^2
= h^2/h^2
= 1
==================
= (P/h)^2 + (b/h)^2
= (p^2/h^2) + (b^2/h^2)
= (p^2 + b^2)/h^2
= h^2/h^2
= 1
==================
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