Question

sin square28-cos square62​

Answer 1

Answer:

${ \huge{ \underline{ \sf{ \red{ Solution:}}}}}$

${ \sf{ {sin}^{2} 28 - {cos}^{2} 62}}$

$\to{ \sf{ {sin}^{2}28 - {cos}^{2} (90 - 28) }}$

$\to{ \sf{ {sin}^{2} 28 - {sin}^{2} 28 = 0}}$

${ \therefore \: { \sf{ {sin}^{2} 28 - {cos}^{2} 62 = 0}}}$

Explanation:

Extra information:-

• Sin(90 - θ) = cosθ

• Cos(90 - θ) = Sinθ

• Tan(90 - θ) = Cotθ

• Cot(90 - θ) = Tanθ

• Cosec(90 - θ) = Secθ

• Sec(90 - θ) = Cosecθ