sin squared theta + cos squared theta equals to 1
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hey friend your answer is
it is the formula sin^2theta+cos^2 theta =1
it is the formula sin^2theta+cos^2 theta =1
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It depends on which definition we use. If we use the unit circle, then the definition includes this phrase so I call the unit circle variant done.
Let’s get to the normal triangle thing. Then sinx=acsinx=ac and cosx=bccosx=bc. Then sin2x+cos2x=a2+b2c2sin2x+cos2x=a2+b2c2, which is indeed 1 (by the Pythagorean identity; c is the hypotenuse).
The differential variant actually is harder (and I don’t yet have the formal tools to prove it this way, although it’s definitely of genuine interest to me: exploring differential equations and consequences of the definition as solution to the equation)
hope it will help you ✨✌️✨✌️✨✌️
Let’s get to the normal triangle thing. Then sinx=acsinx=ac and cosx=bccosx=bc. Then sin2x+cos2x=a2+b2c2sin2x+cos2x=a2+b2c2, which is indeed 1 (by the Pythagorean identity; c is the hypotenuse).
The differential variant actually is harder (and I don’t yet have the formal tools to prove it this way, although it’s definitely of genuine interest to me: exploring differential equations and consequences of the definition as solution to the equation)
hope it will help you ✨✌️✨✌️✨✌️
RahulNani888:
Noor
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