Sin tan ÷ 1-cos = (1 + Sec ). plz help me guy's
Answers
Answered by
0
Answer: sinA*sinA/cosA) /(1-cosA)
sin^2A/(cosA (1-cosA ))
(1-cos^2A)/ (cosA (1-cosA))
(1+cosA)(1-cosA) / (cosA (1-cosA))
(1+cosA)/cosA
(1/cosA)+(cosA/cosA)
secA+1
1+secA proved
Step-by-step explanation:
Similar questions